Jeffrey's dogs ate 42 pounds of food during July. At that rate, how many days would a 100 pound bag of dog food would last? Round to the nearest whole day.
42/31 = 100/x
Cross multiply and solve for x.
42x = 3100
x = 73.8 = 74 days
Jeffrey's dogs ate 42 pounds of food during July. At that rate, which is closest to the number of days a 100-pound bag of dog food would last?
To find out how many days a 100 pound bag of dog food would last, we need to determine the rate at which Jeffrey's dogs consumed food.
We know that Jeffrey's dogs ate 42 pounds of food during July. Let's calculate the rate of food consumption per day:
42 pounds / 31 days (in July) = 1.355 pounds per day (rounded to three decimal places)
Now, we can determine how many days a 100 pound bag of dog food would last by dividing the weight of the bag by the rate of food consumption:
100 pounds / 1.355 pounds per day = 73.82 (rounded to two decimal places)
Therefore, a 100 pound bag of dog food would last approximately 74 days (rounded to the nearest whole day).
To figure out how many days a 100-pound bag of dog food would last, we can use a simple ratio.
Jeffrey's dogs ate 42 pounds of food in July. Now we can set up a proportion to find out how many days a 100-pound bag of dog food would last.
The proportion can be set up like this:
42 pounds --> 1 day
100 pounds --> x days
To solve for x, we can use cross multiplication.
42 * x = 100 * 1
42x = 100
Now, divide both sides by 42 to find the value of x.
x = 100 / 42
x ≈ 2.38 (rounded to two decimal places)
Therefore, a 100-pound bag of dog food would last approximately 2.38 days. Since we need to round to the nearest whole day, the answer would be 2 days.