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Chemistry

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What mass of hydrochloric acid (in grams) can be neutralized by 2.3g of sodium bicarbonate(Hint: Begin by writing a balanced equation for the reaction between aqueous sodium bicarbonate and aqueous hydrochloric acid.)

  • Chemistry -

    NaHCO3 + HCl -> NaCl + CO2 + H2O

    n(NaHCO3)=n(HCl)
    n(NaHCO3)=m/M=2.3g/83.99*(g/mol)=0.027384 mol

    m(HCl)=n*M
    m(HCl)=0.027384 mol * 36.46 (g/mol)= 0.9984 g

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