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November 29, 2014

November 29, 2014

Posted by **Daksh** on Saturday, August 3, 2013 at 8:37pm.

- Maths- Calculus -
**Reiny**, Saturday, August 3, 2013 at 9:15pmlet each side of the squares to be cut out be x cm

length = 80-2x

width = 55-2x , 0 < x < 27.5

height = x

V = x(80-2x)(55-2x)

= 4x^3 -270x^2 + 4400x

dV/dx = 12x^2 - 540x + 4400

= 0 for a max of V

3x^2 - 135x + 1100 = 0

x = (135 ± √5025)/6

take it from there (I get x = appr 10.69)

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