Thursday
July 24, 2014

Homework Help: Analytical chemistry

Posted by Gloria on Saturday, August 3, 2013 at 1:40pm.

The iron in a 0.6656 g ore sample was reduced quantitatively to the +2 state and then titrated with 26.753 g of KMnO4 solution. Calculate the percent Fe2O3 in the sample.

the mass i get for fe2o3 is too big, but i don't know how else to do this problem, someone please help :S

5Fe + Mno4 -> 5Fe + Mn
n(MnO4)=26.753/158=0.1693 mol
n(Fe)=5*n(MnO4)=0.8466139 mol

2Fe->Fe2O3
m(Fe2O3)=0.8466139*159.7*(1/2)=67.6 g

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