Posted by **harsha ojha** on Saturday, August 3, 2013 at 6:00am.

a man stand on the top of the building 490 m above the ground.he throws a stone horizontally with speed15 m/s.find the time taken by the stone to reach the ground &the speed with which it hits the ground

- physics -
**Elena**, Saturday, August 3, 2013 at 6:10am
h=gt²/2

t=sqrt(2h/g)

v(y) = gt

v(x) =15 m/s

v= sqrt{v(x)²+v(y)²}

- physics -
**vanessa**, Wednesday, September 18, 2013 at 4:28pm
A ball is thrown vertically upward with an

initial speed of 28 m/s. Then, 1.7 s later, a

stone is thrown straight up (from the same

initial height as the ball) with an initial speed

of 33.3 m/s.

How far above the release point will the ball

and stone pass each other? The acceleration

of gravity is 9.8 m/s^2

Answer in units of m

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