Posted by Jayden Haddy on Saturday, August 3, 2013 at 12:24am.
solve the equation
express the answers in p and q
x(square)  (p+q)x + (p+1)(q1)=0
Then x=? or x=?

maths  Jai, Saturday, August 3, 2013 at 2:26am
Recall that in a quadratic equation,
x^2  (sum of roots)x + (product of roots) = 0
or if we let a & b the roots,
x^2  (a+b) + (a)(b) = 0
From the given equation, we can see that the constant term is factored, which is (p+1)(q1). Now, let's assume that the roots are p+1 and q1. We then check its sum if it is equal to p+q. If it is, then they are the roots of the equation:
p + 1 + q  1 = p + q
Therefore the roots are p+1 and q+1.
Another way to solve this is to use the quadratic equation:
x = [b +/ sqrt(b^2  4ac)] / 2a
You should get the same answer.
Hope this helps~ :)

mathstypo  Jai, Saturday, August 3, 2013 at 2:32am
*I mean the roots are p+1 and q1.
Just a typo error. Sorry about that. :3
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