Saturday

October 25, 2014

October 25, 2014

Posted by **Jayden Haddy** on Saturday, August 3, 2013 at 12:24am.

express the answers in p and q

x(square) - (p+q)x + (p+1)(q-1)=0

Then x=? or x=?

- maths -
**Jai**, Saturday, August 3, 2013 at 2:26amRecall that in a quadratic equation,

x^2 - (sum of roots)x + (product of roots) = 0

or if we let a & b the roots,

x^2 - (a+b) + (a)(b) = 0

From the given equation, we can see that the constant term is factored, which is (p+1)(q-1). Now, let's assume that the roots are p+1 and q-1. We then check its sum if it is equal to p+q. If it is, then they are the roots of the equation:

p + 1 + q - 1 = p + q

Therefore the roots are p+1 and q+1.

Another way to solve this is to use the quadratic equation:

x = [-b +/- sqrt(b^2 - 4ac)] / 2a

You should get the same answer.

Hope this helps~ :)

- maths-typo -
**Jai**, Saturday, August 3, 2013 at 2:32am*I mean the roots are p+1 and q-1.

Just a typo error. Sorry about that. :3

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