a 2500kg car is rounding a circular turn of radius 200m at constant speed. the magnitude of its acceleration is 2m/s2.what is the speed of the car? how much is the centripetal force?how much is the centrifugal acceleration?
Centripetal (centrifugal ) acceleration a= 2 m/s²
a=v²/R
v=sqrt(aR) =sqrt(2•200) =20 m/s
Centripetal force is F=ma= 2500•2 = 5000 N
http://www.engineeringtoolbox.com/centripetal-acceleration-d_1285.html
For the speed of the car (V), solve
V^2/R = 2 m/s^2
V = sqrt400 = 20 m/s
The centripetal force is
(acceleration)*(Mass) = 2*2500 = 5000 N
Centrifugal acceleration is the opposite of centripetal acceleration
To find the speed of the car, we can use the equation for centripetal acceleration:
a = v^2 / r
where:
a = centripetal acceleration
v = speed of the car
r = radius of the circular turn
Given that the magnitude of the acceleration is 2 m/s^2 and the radius is 200 m, we can rearrange the equation to solve for the speed:
v = √(a * r)
= √(2 m/s^2 * 200 m)
= √(400 m^2/s^2)
= 20 m/s
Therefore, the speed of the car is 20 m/s.
To find the centripetal force acting on the car, we can use the equation:
F = m * a
where:
F = centripetal force
m = mass of the car
Given that the mass of the car is 2500 kg and the acceleration is 2 m/s^2, we can calculate the centripetal force:
F = 2500 kg * 2 m/s^2
= 5000 N
Therefore, the centripetal force acting on the car is 5000 N.
Now, let's address the centrifugal acceleration. The term "centrifugal" refers to an apparent force experienced by an object moving in a curved path, which is equivalent in magnitude but opposite in direction to the centripetal force. Centrifugal acceleration can be calculated using the same formula as centripetal acceleration:
a_centrifugal = v^2 / r
Substituting the given values, we have:
a_centrifugal = (20 m/s)^2 / 200 m
= 400 m^2/s^2 / 200 m
= 2 m/s^2
Therefore, the centrifugal acceleration is 2 m/s^2.