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March 29, 2015

March 29, 2015

Posted by **Tom** on Tuesday, July 30, 2013 at 1:52pm.

- statistics -
**MathGuru**, Tuesday, July 30, 2013 at 6:58pmTry this formula:

n = [(z-value)^2 * p * q]/E^2

= [(1.96)^2 * .2 * .8]/.05^2

I'll let you finish the calculation.

Note: n = sample size needed; .2 (20%)for p and .8 (which is 1 - p) for q. E = maximum error, which is .05 (5%) in the problem. Z-value is found using a z-table (for 95%, the value is 1.96). Symbols: * means to multiply and ^2 means squared.

I hope this will help get you started.

- statistics -
**Anonymous**, Tuesday, May 13, 2014 at 11:37amhkjhkbh809089809

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