Posted by **Joy** on Tuesday, July 30, 2013 at 4:50am.

If f(x) = log2 (x - 2)3 and g(x) = log8 (x - 2), when is (f + g)(x) = 0?

- Discrete Mathematics -
**Steve**, Tuesday, July 30, 2013 at 4:53am
working with logs base 2,

since 8=2^3, g(x) = 1/3 log(x-2)

(f+g)(x) = f(x)+g(x)

= 3log(x-2) + 1/3 log(x-2)

= 10/3 log(x-2)

so, if (f+g)(x) = 0,

log(x-2) = 0

x-2 = 1

x = 3

check

log_2(3-2)^3 = 0

log_8(3-2) = 0

- Discrete Mathematics -
**Joy**, Tuesday, July 30, 2013 at 6:36am
Thanks Steve! I am starting to write these down so that way I will understand them. It is easier for me to go off an example. I appreciate all your help.

## Answer This Question

## Related Questions

- Math - The problem I have to solve is log with base 2 ^6 multiply by log base 6...
- Math - Hello! Could someone please take a look at the problem below and let me ...
- Math - I don't understand how log2 √(1/2) turned into log2 2^(-1/2). ...
- Math - I don't understand how log2 √(1/2) turned into log2 2^(-1/2). ...
- Math - I don't understand how log2 √(1/2) turned into log2 2^(-1/2). Quote...
- Urgent math - i need help with these two homework problems Use the Laws of ...
- Discrete Math - There are 150 students taking Discrete Mathematics II, Calculus ...
- math - solve the equation log2(x+4)-log4x=2 the 2 and 4 are lower than the g ...
- College Algebra - I REALLY don't understand the reason/basis/use of logarithms. ...
- Logarithms - I'm working on logarithmic equations and I'm stuck on how my book ...

More Related Questions