thirty animals are to be used in a medical experiment on diet deficiency: 3 male and 7 female rhesus monkeys, 6 male and 8 female dogs. If one animal is selected at random, what is the probability of getting a chimpanzee or a dog?
Of the 30 animals, (3+7)+(6+8)=24 are rhesus monkey or dog.
No idea how many chimps there are.
To find the probability of selecting a chimpanzee or a dog, we need to determine the total number of chimpanzees and dogs in the group and divide it by the total number of animals available.
From the given data, we know that there are no chimpanzees mentioned. Hence, we only need to consider the probability of selecting a dog.
There are a total of 6 male dogs and 8 female dogs, which gives us a total of 6 + 8 = 14 dogs.
Now, let's calculate the probability of selecting a dog:
Probability = Number of favorable outcomes / Total number of possible outcomes
Number of favorable outcomes = Number of dogs = 14
Total number of possible outcomes = Total number of animals = 30
Probability of selecting a dog = 14 / 30 = 7 / 15
Therefore, the probability of selecting a dog from the group is 7/15.