physics
posted by sammi on .
A diver springs vertically upward with an initial speed of 1.7 m/s from a diving board
that is 3.2 m above the water. Find the speed with which she enters the water, assuming
completely vertical motion.

mv₀²/2= mgh
h= v₀²/2g
mg(H+h) = mv²/2
mgH +mv₀²/2 = mv²/2
v=sqrt{ v₀² +gH} =
= sqrt{1.7²+9.8•3.2} = 5.85 m/s