Thursday

September 18, 2014

September 18, 2014

Posted by **James** on Monday, July 29, 2013 at 1:15pm.

Sample size: 36 students Sample mean: 29.643 years

Sample standard deviation: 4.564 years

a. Calculate the standard error of this sample mean.

b. Determine and interpret a 90% confidence interval for the mother’s mean age (at student’s birth) in the population of all students at this university.

c. How would a 99% confidence interval compare to the 90% interval in terms of its midpoint and half-width?

d. Would you expect 90% of the ages in the sample to be within the 90% confidence interval? Explain why or why not.

e. Even if the distribution of mothers’ ages were somewhat skewed, would this confidence interval procedure still be valid with these data? Explain why or why not.

- Math Statistics -
**Chol**, Monday, July 29, 2013 at 4:11pma. The standard error of the sample mean is 4.564/sqrt(36) = 0.7607

b. yes The mother's mean age student birth lie in interval (28.358, 30.928)

**Answer this Question**

**Related Questions**

statistics - A random sample of 36 statistics students were asked to add a ...

statistics - An IQ is designed so that the mean is 100 and the standard ...

Statistics - In the population of typical college students, _ 5 75 on a ...

Statistics - An IQ test is designed so that the mean is 100 and the standard ...

statistics - The average age of evening students at a local college has been 21...

statistics - In a study of the effect of college student employment on academic ...

statistics - Professor Smith conducted a class exercise in which students ran a ...

Statistics - A group of statistics students decided to conduct a survey at their...

Statistics - A group of statistics students decided to conduct a survey at their...

Statistics - 28. A group of statistics students decided to conduct a survey at ...