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February 27, 2015

February 27, 2015

Posted by **James** on Monday, July 29, 2013 at 1:15pm.

Sample size: 36 students Sample mean: 29.643 years

Sample standard deviation: 4.564 years

a. Calculate the standard error of this sample mean.

b. Determine and interpret a 90% confidence interval for the mother’s mean age (at student’s birth) in the population of all students at this university.

c. How would a 99% confidence interval compare to the 90% interval in terms of its midpoint and half-width?

d. Would you expect 90% of the ages in the sample to be within the 90% confidence interval? Explain why or why not.

e. Even if the distribution of mothers’ ages were somewhat skewed, would this confidence interval procedure still be valid with these data? Explain why or why not.

- Math Statistics -
**Chol**, Monday, July 29, 2013 at 4:11pma. The standard error of the sample mean is 4.564/sqrt(36) = 0.7607

b. yes The mother's mean age student birth lie in interval (28.358, 30.928)

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