An LSU football defender is 6 m behind a Georgia Tech receiver who has the football
and is d meters from making a touchdown. If the LSU player is running at 5 m/s and the
receiver is running at 4 m/s, what is the furthest distance, d, that the Tech player can be
from the goal line and still make a touchdown?
physics - Henry, Monday, July 29, 2013 at 9:26pm
Eq1: 4*t = d
Eq2: 5*t = 6 + d
In Eq2, replace d with 4t:
5t = 6 + 4t
5t-4t = 6
t = 6 s.
In Eq1, replace t with 6:
d = 4 * 6 = 24 m.