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math

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find the domain, target, and rule of the inverse functions:
1. f(x)=(x+3)/(5x+2)
2. g(x)=1/square root of 2x-1

  • math -

    y = (x+3)/(5x+2)
    5xy+2y = x+3
    (5y-1)x = 3-2y
    x = (3-2y)/(5y-1)

    So, the inverse function is (3-2x)/(5x-1)

    y = 1/√(2x-1)
    y^2 = 2x-1
    x = (y^2+1)/2

    So, g^-1(x) = (x^2+1)/2

    You can probably figure out the rest.

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