How many moles of O2 are produced when 0.300mol of KO2 reacts in this fashion?

What fashion?

To determine the number of moles of O2 produced when 0.300 mol of KO2 reacts, we first need to understand the balanced equation for the reaction.

The balanced equation for the reaction between KO2 and O2 is:
2KO2 -> 2K2O + O2

From the equation, we can see that for every 2 moles of KO2 that react, 1 mole of O2 is produced.

Therefore, if we have 0.300 mol of KO2, we can calculate the number of moles of O2 produced as follows:

Number of moles of O2 = (0.300 mol KO2) x (1 mol O2 / 2 mol KO2)

Using the given information, we can perform the calculation:

Number of moles of O2 = 0.300 mol KO2 × 1 mol O2 / 2 mol KO2

Number of moles of O2 = 0.150 mol O2

So, 0.150 mol of O2 is produced when 0.300 mol of KO2 reacts.

To determine the number of moles of O2 produced, we need to know the balanced chemical equation for the reaction. However, since you haven't provided that information, I'll use a hypothetical example to explain how to calculate the moles of O2 produced.

Let's say the balanced equation for the reaction is:
2 KO2 → 2 K + O2

According to this equation, 2 moles of KO2 produce 1 mole of O2. Therefore, in order to find out how many moles of O2 are produced when 0.300 moles of KO2 react, we can set up a proportion using this ratio:

2 moles KO2 : 1 mole O2 = 0.300 moles KO2 : x moles O2

To solve for x (the number of moles of O2 produced), we can use cross-multiplication. So, the equation becomes:

(2/1) = (0.300/x)

Now, cross-multiply and solve for x:

2x = 0.300 * 1
2x = 0.300
x = 0.150 mol

Therefore, when 0.300 mol of KO2 reacts, it produces 0.150 mol of O2.

ANSWER n(O2) = 0.225 mol