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December 20, 2014

December 20, 2014

Posted by **Claudia** on Friday, July 26, 2013 at 10:26pm.

2.solve 4(3^2x)=e^x

- math -
**Reiny**, Friday, July 26, 2013 at 10:56pm1. take ln of both sides

ln(x e^x)^2 = ln(30 e^-x)

2 lnx + 2ln e^x = ln30 + ln e^-x

2lnx + 2x = ln30 -x

2 lnx = -3x + ln30

lnx = (-3/2)x + (1/2)ln30 or (-3/2)x + ln (√30)

comparing this with ax + b

a = -3/2 , b = ln √30

2. take ln of both sides and use rules of logs

ln (4(3^2x) ) = ln e^x

ln4 + xln3 = x

x - 2xln3 = ln4

x(1 - 2ln3) = ln4

x = ln4/(1-2ln3) or appr. -1.1579

check:

LS = 4(3^-2.3158... = .31413784

RS = e^-1.157923.. = .31413784 , how about that?

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