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Posted by on Friday, July 26, 2013 at 7:58pm.

During a rain storm, rain comes straight down with velocity Vi =-15 m/s and hits the roof of a car perpendicularly. The mass of the rain per second that strikes the roof is 0.060 kg every second. Assuming that the rain comes to rest upon strikingthe car ( Vf = 0 m/s), find the average force exerted by rain on the roof during a 3 second time interval.

  • Physical Science/Physics - , Friday, July 26, 2013 at 9:16pm

    F=Ma

    F=M(∆V/t)

    ∆V=Vf-Vi=-15m/s-0m/s=-15m/s
    t=3s
    m=0.060 kg

    Plug and chug

    F=(0.060 kg)[(-15m/s)/3s]

  • scince - , Saturday, July 27, 2013 at 7:29am

    The time interval doesn't matter.

    F = (0.060 kg/s)(15 m/s) = 0.90 N

  • scince - , Monday, May 12, 2014 at 1:59am

    I think that it would: F=ma, and F=mdV

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