Posted by trina on Friday, July 26, 2013 at 7:58pm.
During a rain storm, rain comes straight down with velocity Vi =15 m/s and hits the roof of a car perpendicularly. The mass of the rain per second that strikes the roof is 0.060 kg every second. Assuming that the rain comes to rest upon strikingthe car ( Vf = 0 m/s), find the average force exerted by rain on the roof during a 3 second time interval.

Physical Science/Physics  Devron, Friday, July 26, 2013 at 9:16pm
F=Ma
F=M(∆V/t)
∆V=VfVi=15m/s0m/s=15m/s
t=3s
m=0.060 kg
Plug and chug
F=(0.060 kg)[(15m/s)/3s]

scince  drwls, Saturday, July 27, 2013 at 7:29am
The time interval doesn't matter.
F = (0.060 kg/s)(15 m/s) = 0.90 N

scince  Devron, Monday, May 12, 2014 at 1:59am
I think that it would: F=ma, and F=mdV
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