The complex [Co(ox)3]4- has a high-spin electron configuration. How many unpaired electrons are there in the complex?
I know because it's a high-spin, it's tetrahydral shaped. But I don't know what (ox) is so, I'm stuck in finding the oxidation state of Co which helps me find the number of electrons.
Chemistry - DrBob222, Friday, July 26, 2013 at 6:04pm
Oxalic acid is H2C2O4 so oxalate is the C2O4^2- part. So that makes Co 2+. right?
(Co usually is +2 or +3)
Chemistry - Sara, Friday, July 26, 2013 at 6:10pm
Okay, cool. So, the oxidation state of Co is 2+.
Co2+ = [Ar]4s2 3d7
Metal cations get rid of the s orbital before the d, so can I say then the number of unpaired electrons is 7?
Chemistry - DrBob222, Friday, July 26, 2013 at 7:52pm
For high spin, yes.