How many moles of HNO3 are present in 34.0 mL of a 4.70 M solution of nitric acid?
mols = M x L = ?
ANSWER ν = 0.160 mol
To find the number of moles of HNO3 present in the given solution, we can use the formula:
Moles = (Concentration) x (Volume in liters)
First, we need to convert the volume from milliliters to liters by dividing it by 1000:
34.0 mL ÷ 1000 = 0.034 L
Now we can calculate the number of moles using the formula:
Moles = (4.70 M) x (0.034 L)
Moles = 0.1598
Therefore, there are approximately 0.1598 moles of HNO3 present in 34.0 mL of a 4.70 M solution of nitric acid.