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March 27, 2015

March 27, 2015

Posted by **Elyse** on Thursday, July 25, 2013 at 2:32pm.

f(t) = cos^(2)(2t)

- Calculus-HELP!!! -
**Steve**, Thursday, July 25, 2013 at 3:10pmcos^2(2t)

L{cos(t)} = s/(s^2+1)

L{f(at)} = 1/a f(s/a), so

L{cos(4t)} = 1/4 (s/4)/(s^2/16+1) = s/(s^2+6)

L{cos^2(2t)} = L{(1+cos(4t))/2}

= 1/2 (L{1} + L{cos(4t)})

= 1/2 (1/s + s/(s^2+16))

= (s^2+8) / (s^3+16s)

- Calculus-HELP!!! -
**Elyse**, Thursday, July 25, 2013 at 3:43pmThank you!!

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