posted by justin on .
An aluminum can is filled to the brim with a liquid. The can and the liquid are heated so their temperatures change by the same amount. The can’s initial volume at 8 °C is 4.8 × 10-4 m3. The coefficient of volume expansion for aluminum is 69 × 10-6 (C°)-1. When the can and the liquid are heated to 80 °C, 6.1 × 10-6 m3 of liquid spills over. What is the coefficient of volume expansion of the liquid?
The volume of liquid that spills over the can is the difference between the increase in the volume of the liquid and that of the aluminum can
ΔV=β₁VΔT - β ₂VΔT
β₁=(ΔV/VΔT) + β ₂ =
=(6.1•10⁻⁶/4.8•10⁻⁴•72) + 69•10⁻⁶ = 1.13•10⁻³ °C⁻¹