Friday

December 19, 2014

December 19, 2014

Posted by **andy** on Thursday, July 25, 2013 at 2:11pm.

- calculus -
**Steve**, Thursday, July 25, 2013 at 2:53pmThe region is the upper half of a circle with radius 1/2 centered at (1/2,0):

(x-1/2)^2 + y^2 = 1/4

So,

∫[0,1]∫[0,√1/4 - (x-1/2)^2) 1/√(x^2+y^2) dy dx

recall that √1/(x^2+y^2) dy = arcsinh(y/x) = log(x + √(x^2+y^2))

- calculus -
**Steve**, Thursday, July 25, 2013 at 2:54pmoops that's log(y + √(x^2+y^2))

**Answer this Question**

**Related Questions**

Calculus - Evaluate ∬R xy dA, where R is the region bounded by x^2+y^2&#...

calculus - Let V be the volume of the region bounded by x^2+y^2≥z^2, z&#...

calculus - Let V be the volume of the three-dimensional structure bounded by the...

Calculus - Let V be the volume of the three-dimensional structure bounded by the...

calculus (point me in the right direction please?) - Let V be the volume of the ...

Calculus - Find the area of the region enclosed by y−2x^2 ≥ 0 and |...

Calculus:) - Find the area of the region enclosed by y−2x^2≥0 and |x...

Calculus:) - Find the area of the region enclosed by y−2x^2≥0 and |x...

math - Maximize and minimize p = x + 2y subject to x + y ≥ 8 x + y ≤...

linear programming - Minimize z = 3x + 6y subject to: 4x + y ≥ 20 x + y...