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October 1, 2014

October 1, 2014

Posted by **andy** on Thursday, July 25, 2013 at 2:10pm.

- calculus -
**Steve**, Thursday, July 25, 2013 at 2:44pmThe region is inside a sphere, outside the cone. So, just find the volume of the cone with a spherical cap, and subtract that from half the sphere.

a web search will quickly provide the formulas needed.

Or, you can resort to a volume integral, most easily done using spherical coordinates.

- calculus -
**andy**, Thursday, July 25, 2013 at 3:08pmcould you give me a bit help on how to proceed if I were to use a volume integral?

- calculus -
**Steve**, Thursday, July 25, 2013 at 3:27pmthe cone is φ = π/4

the sphere is r = 1

dV = r^2 sinφ dφ dθ dr

V = ∫[0,1]∫[0,2π]∫[0,π/4] r^2 sinφ dφ dθ dr

Good luck. Probably ought to verify with cone/sphere formulas to be sure.

- calculus -
**andy**, Thursday, July 25, 2013 at 3:39pmok, thanks

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