Posted by **sushil** on Thursday, July 25, 2013 at 12:41pm.

A round bar 40 mm dia meter is subjected to an axial pull of 80 kn and reduction in diameter was found to be 0.00775mm.find poisson's ratio and young's modules for the material of the bar. take value of shear modules as 40kn/mm square.

- solid mechanics -
**MathMate**, Thursday, July 25, 2013 at 2:14pm
Assuming an isotropic and elastic material,

εy=-0.00775/40

σx=80 kN

G=40 N/mm^2 (40 kN was probably a typo)

Use

εy=(σy-ν(σx+σz))/E ....(1)

and

G=E/[2(1+ν)] ...(2)

Solve for ν by substituting

E=2G(1+ν) from (2)

into (1)

εy=(σy-ν(σx+σz))/[2G(1+ν)]

and solve for ν.

Substitute ν into (2) to find E.

I get ν=0.24, E=99.2 MPa

- solid mechanics -
**prasad**, Tuesday, August 12, 2014 at 1:21am
Give the answer

## Answer this Question

## Related Questions

- Solid Mechanics - A round bar 40 mm dia meter is subjected to an axial pull of ...
- math - A round bar 40mm diameter is subjected to an axial pull of 80kN and ...
- solid mechanics - A round bar 40 mm diameter was found to be 0.000775 mm. Find ...
- solid mechanics - A piece of material subjected to three mutually perpendicular ...
- Physic - Reaction at support and internal axial force resultant Consider two ...
- psuchics - Reaction at support and internal axial force resultant Consider two ...
- physics - Consider two straight bars of uniform cross section made of the same ...
- sakre school - A piece of material subjected to three mutually perpendicular ...
- Physics - The cylindrical bar in the figure has a total length L=1.2 m, a ...
- solid mechanics - a steel bar 10m long and 10cm*10cm in section .it is subjected...

More Related Questions