Posted by **sushil** on Thursday, July 25, 2013 at 12:41pm.

A round bar 40 mm dia meter is subjected to an axial pull of 80 kn and reduction in diameter was found to be 0.00775mm.find poisson's ratio and young's modules for the material of the bar. take value of shear modules as 40kn/mm square.

- solid mechanics -
**MathMate**, Thursday, July 25, 2013 at 2:14pm
Assuming an isotropic and elastic material,

εy=-0.00775/40

σx=80 kN

G=40 N/mm^2 (40 kN was probably a typo)

Use

εy=(σy-ν(σx+σz))/E ....(1)

and

G=E/[2(1+ν)] ...(2)

Solve for ν by substituting

E=2G(1+ν) from (2)

into (1)

εy=(σy-ν(σx+σz))/[2G(1+ν)]

and solve for ν.

Substitute ν into (2) to find E.

I get ν=0.24, E=99.2 MPa

- solid mechanics -
**prasad**, Tuesday, August 12, 2014 at 1:21am
Give the answer

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