Wednesday

April 16, 2014

April 16, 2014

Posted by **sushil** on Thursday, July 25, 2013 at 12:41pm.

- solid mechanics -
**MathMate**, Thursday, July 25, 2013 at 2:14pmAssuming an isotropic and elastic material,

εy=-0.00775/40

σx=80 kN

G=40 N/mm^2 (40 kN was probably a typo)

Use

εy=(σy-ν(σx+σz))/E ....(1)

and

G=E/[2(1+ν)] ...(2)

Solve for ν by substituting

E=2G(1+ν) from (2)

into (1)

εy=(σy-ν(σx+σz))/[2G(1+ν)]

and solve for ν.

Substitute ν into (2) to find E.

I get ν=0.24, E=99.2 MPa

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