Posted by sushil on .
A round bar 40 mm dia meter is subjected to an axial pull of 80 kn and reduction in diameter was found to be 0.00775mm.find poisson's ratio and young's modules for the material of the bar. take value of shear modules as 40kn/mm square.

solid mechanics 
MathMate,
Assuming an isotropic and elastic material,
εy=0.00775/40
σx=80 kN
G=40 N/mm^2 (40 kN was probably a typo)
Use
εy=(σyν(σx+σz))/E ....(1)
and
G=E/[2(1+ν)] ...(2)
Solve for ν by substituting
E=2G(1+ν) from (2)
into (1)
εy=(σyν(σx+σz))/[2G(1+ν)]
and solve for ν.
Substitute ν into (2) to find E.
I get ν=0.24, E=99.2 MPa 
solid mechanics 
prasad,
Give the answer