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mathematics ,analytical ge0metry

posted by on .

Determine the length of the line segment between the following points.
T(2x;y-2) and U(3x+1;y-2)

  • mathematics ,analytical ge0metry - ,

    Just use the good old Pythagorean Theorem:

    d^2 = ∆x^2 + ∆y^2
    = ((3x+1)^2-(2x)^2)+((y-2)-(y-2))^2
    = (5x^2 + 6x + 1) - (0)
    . . .

  • mathematics ,analytical ge0metry - ,

    Still confused steve can you please elaborate more PLEASE

  • mathematics ,analytical ge0metry - ,

    what Steve meant to say was:

    d^2 = (3x+1 - 2x)^2 + (y-2 - (y-2))^2
    = (x+1)^2 + 0^2
    d =√(x+1)^2
    = x+1

    e.g.
    let x = 3, y = 5
    then T is (6,3) and U is (10,3)
    TU = √(4^2 + 0^2)
    = √16 = 4
    according to my result, d = 3+1 = 4 , as in the test answer.

  • mathematics ,analytical ge0metry - ,

    ouch! Guess I had too many squares working with me!
    What was I thinking?

  • mathematics ,analytical ge0metry - ,

    Thank u guys ...I now understand

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