Posted by **kate** on Wednesday, July 24, 2013 at 11:03pm.

solve my system of equation with full steps

3x+4y=29

2x–5y=-19

- math -
**Anonymous**, Thursday, July 25, 2013 at 12:05am
Multiply I eq by 2 and II by 3

6x+8y=58

6x-15y=-57. Subtract II eq from I. Signs of II eq will change:-6x+15y=57.

Thus, 8y+15y=58+57 Or 23y=115

or y=115/23=5.

Now substitute this in any original eq:

3x-4x5=29 or 3x=29-20=9, hence x=9/3=3

- math -
**olivia**, Wednesday, March 25, 2015 at 4:33pm
6,-1

## Answer this Question

## Related Questions

- Math - Solve for x: 5/x+6+2/x^2+7x+6=3/x+1 5/x+5+2/(x+6)(x+1)=3/x+1 5(x+6)(x+1)/...
- Algebra I - How do you write a system of linear equations in two variables? ...
- Algebra HELP - how to solve this equation in the real number system: 2x^(3) + 3x...
- MATH!!!! AHHH!!! - Im studying for finals! A system of equations is shown below...
- Algebra - Solve the system of equations using substitution. x + 4y = -5 3x - 8y...
- Math - Solve the system by addition or substitution. 3x – 4y = 8 6x – 2y = 10 ...
- Math - I am really have a tough time trying to solve this problem. I think my ...
- Math check please - 1. Solve the system of equations y=2x^2-3 y=3x-1 a)no ...
- Algebra 2 - I need help with this problem because I do not have a graphing ...
- Algebra - I need help with these two problems. I need to have all of the steps ...