Posted by **kate** on Wednesday, July 24, 2013 at 11:03pm.

solve my system of equation with full steps

3x+4y=29

2x–5y=-19

- math -
**Anonymous**, Thursday, July 25, 2013 at 12:05am
Multiply I eq by 2 and II by 3

6x+8y=58

6x-15y=-57. Subtract II eq from I. Signs of II eq will change:-6x+15y=57.

Thus, 8y+15y=58+57 Or 23y=115

or y=115/23=5.

Now substitute this in any original eq:

3x-4x5=29 or 3x=29-20=9, hence x=9/3=3

- math -
**olivia**, Wednesday, March 25, 2015 at 4:33pm
6,-1

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