math
posted by
kate
.
solve my system of equation with full steps
3x+4y=29
2x–5y=19

math 
Anonymous
Multiply I eq by 2 and II by 3
6x+8y=58
6x15y=57. Subtract II eq from I. Signs of II eq will change:6x+15y=57.
Thus, 8y+15y=58+57 Or 23y=115
or y=115/23=5.
Now substitute this in any original eq:
3x4x5=29 or 3x=2920=9, hence x=9/3=3

math 
olivia
6,1