An object with an initial velocity of 5 m/s has a constant acceleration of 2 m/s^2. When its speed is 15 m/s how far has it traveled?
s=(v²-v₀²)/2a
To find out how far the object has traveled, we can use the kinematic equation:
v^2 = u^2 + 2as
Where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.
Let's plug in the given values:
u = 5 m/s (initial velocity)
a = 2 m/s^2 (constant acceleration)
v = 15 m/s (final velocity)
We need to rearrange the equation to solve for s:
s = (v^2 - u^2) / (2a)
Plugging in the values:
s = (15^2 - 5^2) / (2 * 2)
Simplifying:
s = (225 - 25) / 4
s = 200 / 4
s = 50 m
Therefore, when the speed of the object is 15 m/s, it has traveled a distance of 50 meters.