Posted by **Sam** on Wednesday, July 24, 2013 at 1:27pm.

A ball is thrown straight downward from the top of a tall building, with an initial speed of 30 ft/s. Suppose the ball strikes the ground with a speed of 190 ft/s. How tall is the building? Acceleration is -32 ft/s squared

- calculus -
**Henry**, Wednesday, July 24, 2013 at 2:25pm
V^2 = Vo^2 + 2g*h

h = (V^2-Vo^2)/2g

h = ((190)^2-(30)^2)/64 = 550 Fi.

- calculus -
**Reiny**, Wednesday, July 24, 2013 at 5:05pm
height = -16t^2 -30t + d, where d is the height of the building

d(height)/dt = velocity = -32t - 30

-190 = -32t - 30

32t = + 160

t = 5

at t = 5 , height = 0

0 = -16(25) - 150 + d

550 = d

## Answer This Question

## Related Questions

- physics - A ball is thrown from the top of a building upward at an angle of 66...
- Physics - A ball is thrown upward from the top of a 24.6 m tall building. The ...
- physic - A ball is thrown upward from the top of a 24.4 m tall building. The ...
- Physics - A ball is thrown upward from the top of a 50.0 m tall building. The ...
- physics - A ball is thrown upward from the top of a 40.0 m tall building. The ...
- physics - A ball is thrown upward from the top of a 24.4-m-tall building. The ...
- Physics - Ball A is thrown straight down off the top of a tall building with an ...
- Physics - A baseball is projected horizontally from the top of a building with ...
- Physics - A ball is thrown horizontally from the building roof at a speed of 20 ...
- Physics/Science #3 - A ball is thrown vertically downward from the top of a 35.9...

More Related Questions