Posted by MIA on .
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green.
Compute the probability that two randomly selected peanut M&M’s are both blue.
If you randomly select two peanut M&M’s, compute that probability that neither of them are red.
If you randomly select two peanut M&M’s, compute that probability that at least one of them is red.

STATISTICS 
Graham,
The probabilities of colors of each pill are independent.
Let m[n] = C, be the event that the [n]th pill is a color (C). eg: P(m1=Blue) = 0.12
(1)
P(m1=Blue and m2=Blue) = P(m1=Blue) P(m2=Blue)
(2)
P(m1<>Red and m2<>Red) =
(1P(m1=Red))(1P(m2=Red))
(3)
P(m1=Red or m2=Red) = P(m1=Red) + P(m2=Red)  P(m1=Red) P(m2=Red) 
STATISTICS 
Anonymous,
12%

STATISTICS 
Anonymous,
1) .0529