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June 29, 2015

June 29, 2015

Posted by **Emma** on Tuesday, July 23, 2013 at 11:12pm.

- Math -
**Reiny**, Wednesday, July 24, 2013 at 12:07amf(x) = x^5 - 6x^2 + x + 4

f '(x) = 5x^4 - 12x + 1

= 0 for a max/min

Not an easy equation to solve,

Wolfram shows two real solutions,

x = appr 1.3098 or x = appr .08335

http://www.wolframalpha.com/input/?i=5x%5E4+-+12x+%2B+1+%3D+0

f(1.3098) = -1.129

f(.08335) = 4.04167

so the y of the local min is appr -1.129