Posted by **Anonymous** on Tuesday, July 23, 2013 at 4:06pm.

The length of a rectangle is 7 centimeters less than twice its width. Its area is 72 square meters. Find the dimensions of the rectangle.

- Algebra world problem -
**Reiny**, Tuesday, July 23, 2013 at 4:43pm
width --- x

length --- 2x-7

x(2x-7) = 72

2x^2 - 7x - 72 = 0

(x-8)(2x+9) = 0

x = 8 or x = -9/2, rejecting the negative width

the rectangle is 8 by 9

- Algebra world problem -
**Chol**, Tuesday, July 23, 2013 at 4:59pm
Let l be 2x -7

w = x

A = lw

72 = (2x-7)x

72 = 2x^2 -7x

2x^2 -7x -72 =0

(2x+9)(x-8) = 0

x -8 = 0

x = 8

l = 2x-7

l = 2(8) -7

l = 16-7= 9

L = 9 m and w =8 m

- Algebra world problem -
**Ms. Sue**, Tuesday, July 23, 2013 at 5:04pm
Aren't the dimensions?

width --- x

length --- 2x-0.07

- Algebra world problem -
**Reiny**, Tuesday, July 23, 2013 at 11:57pm
good catch Ms Sue.

so

x(2x-.07) = 72

2x^2 - .07x - 72 = 0

x = (.07 ± √576.0049)/4

= 6.017 or a negative

width = 6.017

length = 11.965

check: area = 6.017(11.965) = 71.993 , not bad

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