March 1, 2017

Homework Help: Chemistry re-post

Posted by Nancy on Tuesday, July 23, 2013 at 1:52am.

I took a look at this question to see if I copied it correctly, and it does NOT say how much of the solution was used. It does use mols as the unit.

Dr. Bob, I am not sure what you mean by "decays into Argon." I realize that the 38 CL decays to Argon, but how would that work into the solution? I am confused as it appears I need to use PV =NRT and then also half life, but I just don't get 300K as the answer, which is what the book has.

If you have any insight, let me know. If not I will find out later this week how to solve it.


The nuclide 38cl decays by beta emission with a half life of 40min. A sample of .40 mol of H38cl is placed in a 6.24 liter container. After 80 min the pressure is 1650 mmHg. What is temperature of container?

I have tried calculating the decay rate of the 38cl and then plugging into the formula pv =nrt but I do not get the answer, 300 k. Any help would be great.

I would think it would be like this:
.40 mol is .0258% Hydrogen
.40 mole is .974 CL38
.40 x .974=.3896 x half life .25=.0974 + mole of hydrogen .01032
13.54/.1077= 125k but this isn't correct

The correct answer is 300K
anybody know how it was obtained?

Chemistry - DrBob222, Monday, July 22, 2013 at 12:39pm

I'm responding just to let you know that I've looked at the problem more than once over the last day or two. Is the HCl a gas? I suppose no if it is a 0.40 m solution. Is that m and not M? How much of the 0.40m solution? is used? The problem doesn't say. And do you realize that Cl38 goes to Ar38 upon releasing a beta particle.

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