Posted by **isaac** on Monday, July 22, 2013 at 11:55pm.

tap a was turned on to fill a rectangular tank of 50cm by 40cm by 28cm with water at a rate of 6 liters per minute. after 2 minutes, tap b was turned on to drain water from the tank at a rate of 2 liters per minutes. 6 minutes after tap b was turned on, both taps were tuned off. find the depth of water left in the tank

- math -
**Anonymous**, Tuesday, July 23, 2013 at 12:37am
Tap a filled for 8 mins=8x6=48 lit.

Tap b drained for 6 mins=6x2=12 lit.

Water remaining=48-12=36 lit=36000ml

Ht of water in tank=36000/(50x40)=36/2=18 cm

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**Reiny**, Tuesday, July 23, 2013 at 7:42am
A full tank will hold 56 L

Using the calculations of anonymous of 36 L of water after both taps are turned of,

h/28 = 36/56

h = 28(36/56) = 18

the water is 18 cm deep

- math03 -
**Debela Duguma**, Tuesday, July 23, 2013 at 8:08am
Trig aplication meseramants width of lake

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**Debela Duguma**, Tuesday, July 23, 2013 at 8:21am
Haw can solev this qen trig application measruments width of lake?

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