posted by sushil on .
the power developed by a man in riding up a 6 percent grade a ta constant speed is 200 W. the man and his bicycle have acombind mass of 80kg.determine the speed of riding.
gradient = rise/run = 0.06
At 1m/s (horizontal distance), the bike and the rider (mass=80 kg) gains potential energy of mgh
= 80*9.81*(1m/s * 0.06)
= 47.88 W
Therefore speed (in the horizontal direction)
= 200/47.88 m/s (horiz.)
= 4.2474 m/s (horiz.)
= 4.2474*(1.0018) m/s (on slope)
= 4.255 m/s (on slope)