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October 22, 2014

October 22, 2014

Posted by **John Berkhamp** on Monday, July 22, 2013 at 2:09am.

Xn+1=(aXn+c) mod m

X1 is the first pseudo-random number generated, X2 is the second, and so on. Let R be the 2000th pseudo-random number generated by the linear congruential generator when X0=42, a=25, c=31, and m=2^20. What are the last three digits of R?

- Data Structures and Algorithms -
**Aryaman**, Monday, July 22, 2013 at 8:50am938

- Data Structures and Algorithms -
**MathMate**, Monday, July 22, 2013 at 9:11amIf the question asks for the last digits, you could code and evaluate the recursive formula to get the results.

If you would like a check, you are welcome. The sum of the 3 last digits is 20.

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