Physics
posted by Helena Beau on .
A block of mass M=6 kg and initial velocity v=0.8m/s slides on a frictionless horizontal surface and collides with a relaxed spring of unknown spring constant. The other end of the spring is attached to a wall. If the maximum compression of the spring is 0.2 m, what is the spring constant?

Equate kinetic and potential (spring) energies:
KE=(1/2)mv²
PE=(1/2)ks²
Solve for k
k=mv²/s² N/m
(verify that quantities are in consistent units). 
I tried
F=kx so
mg=kx
(6 kg)(9.8m/s^2)=k(0.2m)
k= 294 N/m
But the correct answer is supposed to be 96 Nm. 
Oh I see now. Thanks!

You're welcome!