A sample of oxygen is collected over water at 22 C and 762 torr. What is the partial pressure of the dry oxygen? The vapor pressure of water at 22C is 19.8 torr.

You posted one just like this earlier.

To find the partial pressure of dry oxygen, we need to subtract the vapor pressure of water from the total pressure.

First, write down the information given:
Total pressure (Ptotal) = 762 torr
Vapor pressure of water at 22°C (Pwater) = 19.8 torr

Now, use the formula for partial pressure:
Partial pressure of dry oxygen (Poxygen) = Ptotal - Pwater

Substitute the given values into the formula:
Poxygen = 762 torr - 19.8 torr

Calculate the partial pressure of dry oxygen:
Poxygen = 742.2 torr

Therefore, the partial pressure of dry oxygen is 742.2 torr.