A sample of oxygen is collected over water at 22 C and 762 torr. What is the partial pressure of the dry oxygen? The vapor pressure of water at 22C is 19.8 torr

PTotal = pO2 + pH2O

To find the partial pressure of dry oxygen, we need to subtract the vapor pressure of water from the total pressure.

The total pressure is given as 762 torr, and the vapor pressure of water at 22°C is 19.8 torr.

Partial pressure of dry oxygen = Total pressure - Vapor pressure of water

Partial pressure of dry oxygen = 762 torr - 19.8 torr

Partial pressure of dry oxygen = 742.2 torr