Posted by **Tiff** on Saturday, July 20, 2013 at 6:18am.

Collision derivation problem. A car is released from rest on a frictionless inclined plane. Assume h/L is approximately equal to y/x.

equations.

If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 11/110, the initial displacement is 2.25 m, and the change in momentum is 0.46 kg*m/s, how far will it coast back up the ramp before changing directions? Use equation :

change in momentum = mass [(2g(h/L)]^(1/2) [(L initial)^(1/2) + (L final)^(1/2)]

I keep plugging everything in and get 0.0196 meters, but that is the wrong answer when I type it in. Any help would be very much appreciated, thank you.

- physics -
**brian**, Sunday, July 21, 2013 at 5:39am
I'm really confused on this problem too. Does anyone understand how to do it?????????

- physics -
**brian**, Sunday, July 21, 2013 at 5:40am
I solved and got 0.399m and that was wrong, so I don't know...

## Answer this Question

## Related Questions

- Physics - A 0.9-kg block (mass m) and a second block (mass M) are both initially...
- physics - several students are riding in bumper cars at an amusement park. the ...
- physics - A 2 kg mass resting on a smooth plane inclined 20 degrees to the ...
- physics - Two blocks are connected by a string over a frictionless, massless ...
- physics - A car is released from rest on a frictionless inclined plane. (Figure...
- Physics - A 2.5 kg block sits on an inclined plane with a 30 degree inclination...
- Phsycis/Math (please help) - Two blocks are connected by a string over a ...
- Physics - As shown in the figure below, cars #1 and #2 are sliding across a ...
- Physics - A freight car with a mass of 29,000 kg rolls down an inclined track ...
- physics - the most common reasons for rear - end collisions are too short a ...