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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Friday, July 19, 2013 at 10:21pm.

- Geometry -
**Ms. Sue**, Friday, July 19, 2013 at 10:26pmOne way to solve this is to find the factors of 72. Then see which of these will fit for the perimeter.

- Geometry -
**Reiny**, Saturday, July 20, 2013 at 7:58amlet the length and width be x and y respectively

then

2x + 2y = 44

x + y = 22

y = 22-x

area = xy = 72

x(22-x) = 72

22x - x^2 - 72 = 0

x^2 - 22x + 72 = 0

(x-4)(x-18) = 0

x = 4 or x = 18

if x = 4, then y = 22-4 = 18

if x = 18, then y = 22-18 = 4

the dimensions are 4 by 18 inches

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