Friday

December 19, 2014

December 19, 2014

Posted by **Anonymous** on Friday, July 19, 2013 at 7:34pm.

f '(x) = 3ex - 4x; f(0) = 10

f(x) =

- Calculus -
**Chol**, Friday, July 19, 2013 at 8:36pmf(x) = 3e^x -2x^2 + c

10 = 3e^0 -2(0)^2+ c

10 =3-0+ c

7= c

F(x) = 3e^x -2x^2 + 7

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