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March 26, 2017

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Find f (x) by solving the initial value problem.
f '(x) = 6x^2 - 10x; f(2) = 5
f(x) =

  • Calculus - ,

    I am only going to do one of these because if you have seen one you have seen them all.

    f(x) = 6 (x^3/3) - 10 (x^2/2) + c
    = 2 x^3 - 5 x^2 + c

    no find c by using the one point given
    5 = 2 (2)^3 - 5 (2)^2 + c
    5 = 16 - 20 + c
    c = 9

    so
    f(x) = 2 x^3 - 5 x^2 + 9

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