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September 15, 2014

September 15, 2014

Posted by **Anonymous** on Friday, July 19, 2013 at 7:33pm.

f '(x) = 6x^2 - 10x; f(2) = 5

f(x) =

- Calculus -
**Damon**, Friday, July 19, 2013 at 8:02pmI am only going to do one of these because if you have seen one you have seen them all.

f(x) = 6 (x^3/3) - 10 (x^2/2) + c

= 2 x^3 - 5 x^2 + c

no find c by using the one point given

5 = 2 (2)^3 - 5 (2)^2 + c

5 = 16 - 20 + c

c = 9

so

f(x) = 2 x^3 - 5 x^2 + 9

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