Sunday

January 25, 2015

January 25, 2015

Posted by **ROBIN** on Friday, July 19, 2013 at 7:03pm.

The instantaneous rate of change at x = 2 is zero.

The instantaneous rate of change at x = 3 is negative.

The average rate of change on the interval 0 <x <4 is zero.

- MATH -
**Graham**, Friday, July 19, 2013 at 7:19pmThe instantaneous rate of change at x = 2 is zero.

Means: A peak trough or inflection. The curve levels off there; the tangent is paralel to the x-axis.

The instantaneous rate of change at x = 3 is negative.

Means: There's a downward slop at x=3

The average rate of change on the interval 0 <x <4 is zero.

Means: It's symmetric over the interval - for every up there is a down, and you end as high as you start.

Thus: It's a hill. Plot a parabola with a peak at x=2.

Eg. Plot a curve between points:

(0,0) (1,3) (2,4) (3,3) (4,0)

- MATH -
**Steve**, Saturday, July 20, 2013 at 4:52amGood answer. They didn't actually ask for the function, so the above points (and also many other sets) will work.

**Answer this Question**

**Related Questions**

instantaneous rate of change problem - Joe is investigating the rate of change ...

Instantaneous rate of change - Please help.. Joe is investigating the rate of ...

function rate of change - Joe is investigating the rate of change of the ...

Function: Rate of Change - Joe is investigating the rate of change of the ...

rate of change - Joe is investigating the rate of change of the function y=cos x...

calculus - i'm not sure how to do this. can someone help, please? thanks! ...

Math - Could someone help me with these questions, I don't know question c) and ...

Math~Reinyyy - Could someone help me with these questions, I don't know ...

Math - Instantaneous and average rates of change - a) Describe a graph for which...

Advanced Functions - urgent - Consider the function f(x)=x^3-7X^2+6x-1 A. ...