Posted by **ROBIN** on Friday, July 19, 2013 at 5:53pm.

A frustrated office worker throws his laptop out of his business’s high-rise

office building. The height, h, in meters of the laptop above the ground at t

seconds can be modelled by 2 h(t) 125 5t .

Estimate the instantaneous rate at which the laptop hits the ground.

- MATH -
**ROBIN**, Friday, July 19, 2013 at 5:58pm
sorry the equation is h(t)=125=125-5t^2

- MATH -
**Graham**, Friday, July 19, 2013 at 7:01pm
h(t) = 125 - 5t^2

Take the derivative to find the velocity:

v(t) = dh(t)/dt = -10 t

Now:

Find the time when height is 0.

Find the velocity at that time.

- MATH -
**heather**, Saturday, July 20, 2013 at 12:09pm
but when h is 0 t=0....

- MATH -
**Henry**, Saturday, July 20, 2013 at 7:26pm
h = 125-5t^2 = 0

-5t^2 + 125 = 0

t^2 - 25 = 0

(t+5)(t-5) = 0

t = -5

t = 5 s.

V = g*t = 9.8 * 5 = 49 m/s.

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