Sunday

February 1, 2015

February 1, 2015

Posted by **Anonymous** on Friday, July 19, 2013 at 9:29am.

- Math -
**MathMate**, Friday, July 19, 2013 at 9:52amThe volume to be integrated is bounded by the planes

0≤x≤2

0≤y≤2

z=0

and the surface

z=16-x²-2y².

Thus the volume is given by the triple integral:

V=∫∫∫z dz dx dy

Where z is evaluated from 0 to 16-x²-2y²,

x and y are both evaluated from 0 to 2.

Thus

V=∫∫(16-x²-2y²)dx dy

=∫(88-12y²)/3 dy

=48

**Answer this Question**

**Related Questions**

algebra 1 help please - 4) a student score is 83 and 91 on her first two quizzes...

Algebra 2 - Solve. 4a-2≤a+1≤3a+4 4a-2-1≤a+1-1≤3a+4-1 4a-...

calculus - In spherical coordinates, the inequalities 0≤ρ≤2, 3...

Probability - Random variables X and Y are distributed according to the joint ...

probability - Random variables X and Y are distributed according to the joint ...

Math - Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120...

Math - Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120...

MATH Calculus Homework PLEASE HELP! - Let T be the triangle 1≤x≤2, 0...

Pre Calculus - sec x = -2 , π ≤ x ≤ 3π Use a calculator to...

Healthcare Statistic - Given the following p values, which would be considered ...