A 2.60 kg steel gas can holds 15.0 L of gasoline when full. What is the average density of the full gas can, taking into account the volume occupied by steel as well as by gasoline?
Let ds be the density of steel in kg/liter. Let df be the average density of gasoline. You will need to look it up.
Avg density = [2.6 + 15/df]/[2.6/ds + 15]
Please see answer to ques by Charlie July18 8:28pm
To find the average density of the full gas can, we need to consider the volume occupied by both the steel can and the gasoline.
First, let's find the volume occupied by the steel can. The mass of the steel can is given as 2.60 kg.
To find the volume, we'll use the density formula: density = mass/volume. Rearranging this equation, we find: volume = mass/density.
The density of steel is approximately 7.86 g/cm³ = 7.86 × 10³ kg/m³.
Therefore, the volume of the steel can is: volume of steel = mass of steel / density of steel.
Plugging in the values, we get: volume of steel = 2.60 kg / (7.86 × 10³ kg/m³).
Now, let's find the volume occupied by the gasoline. The volume of gasoline is given as 15.0 L.
Finally, we can calculate the total volume of the full gas can. The total volume is the sum of the volumes of the steel can and the gasoline: total volume = volume of steel + volume of gasoline.
Now that we have the total volume, we can find the average density. The average density is given by: average density = (mass of steel + mass of gasoline) / total volume.
Plugging in the values, we get: average density = (2.60 kg + mass of gasoline) / total volume.
By solving this equation, you can find the average density of the full gas can, taking into account the volume occupied by the steel as well as by the gasoline.