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December 20, 2014

December 20, 2014

Posted by **vincent** on Thursday, July 18, 2013 at 1:17am.

- math -
**Steve**, Thursday, July 18, 2013 at 10:45amis y = -(1/3)x or -1/(3x) ?

- math -
**vincent**, Thursday, July 18, 2013 at 10:48amy = -(1/3)x

- math -
**Steve**, Thursday, July 18, 2013 at 10:52amk = 3x, so x = k/3

ky = (k)(-1/3 x) = -1/3 k (k/3) = -k^2

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