the reaction is......CaCO3+2HCl---->CO2+H2O+CaCl2.
what mass of HCl will be neutralized by 0.50g ofCaCO3?
How do i figure this out in a non-complicated way??
Three steps.
1. mols CaCO3 = grams/molar mass.
2. Using the coefficients in the balanced equation convert mols CaCO3 to mols HCl.
3. Convert mols HCl to grams. g = mols x molar mass.
To determine the mass of HCl that can be neutralized by 0.50g of CaCO3, you need to use stoichiometry and the balanced chemical equation provided.
Step 1: Determine the molar mass of CaCO3 and HCl
- The molar mass of CaCO3 can be calculated by summing the atomic masses of each element: Ca (40.08 g/mol) + C (12.01 g/mol) + 3O (16.00 g/mol) = 100.09 g/mol.
- The molar mass of HCl can be calculated by summing the atomic masses of hydrogen and chlorine: H (1.01 g/mol) + Cl (35.45 g/mol) = 36.46 g/mol.
Step 2: Convert the given mass of CaCO3 to moles
- Use the formula: moles = mass / molar mass.
- moles of CaCO3 = 0.50g / 100.09 g/mol = 0.004997 moles.
Step 3: Use stoichiometry to relate moles of CaCO3 to moles of HCl
- From the balanced equation: 1 mol CaCO3 reacts with 2 mol HCl.
- Therefore, moles of HCl = 2 * 0.004997 moles = 0.009994 moles.
Step 4: Convert moles of HCl to mass
- Use the formula: mass = moles * molar mass.
- mass of HCl = 0.009994 moles * 36.46 g/mol = 0.364 g.
So, 0.50g of CaCO3 will neutralize approximately 0.364g of HCl according to the balanced chemical equation.