Posted by **Alexander** on Tuesday, July 16, 2013 at 1:29pm.

Find the solution set of the equation

{x^2+y^2=34

{x+y=2

- Math -
**Steve**, Tuesday, July 16, 2013 at 2:30pm
just substitute y=2-x and you have

x^2 + (2-x)^2 = 34

2x^2 - 4x - 30 = 0

x^2 - 2x - 15 = 0

now it should be clear ...

- Math -
**Chol**, Tuesday, July 16, 2013 at 2:33pm
y = -x +2

x^2 + (-x +2)^2 = 34

x ^2 + x^2 -2x -2x +4 = 34

2x^2 -4x + 4 = 34

2x^ -4x + 4 -34 = 34-34

2x^2 -4x - 30 = 0

2(x^2 -2x -15) =0

2(x-5)(x+3) =0

x -5 =0

x =5

x+ 3 = 0

x =-3

y = -3 ,5

(5,-3), (-3,5)

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