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Math

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Find the solution set of the equation
{x^2+y^2=34
{x+y=2

  • Math -

    just substitute y=2-x and you have

    x^2 + (2-x)^2 = 34
    2x^2 - 4x - 30 = 0
    x^2 - 2x - 15 = 0
    now it should be clear ...

  • Math -

    y = -x +2

    x^2 + (-x +2)^2 = 34
    x ^2 + x^2 -2x -2x +4 = 34

    2x^2 -4x + 4 = 34
    2x^ -4x + 4 -34 = 34-34
    2x^2 -4x - 30 = 0
    2(x^2 -2x -15) =0

    2(x-5)(x+3) =0
    x -5 =0
    x =5
    x+ 3 = 0
    x =-3

    y = -3 ,5

    (5,-3), (-3,5)

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