posted by hank on .
A hydraulic jack has an input piston with a diameter of 1.00 cm, and an output piston with a diameter of 6.00 cm. What weight (in N) can be lifted when a force of 45.8 N is applied to the input piston?
Answer is 1650 N but I need someone walk me through the steps please.
Wt. = (6.0/1.0)^2 * 45.8 = 1649 N.